### Problem statement

Write a program to take a input number N and find how many even numbers between 0 to N.

### How to find even numbers?

A number which is divisible by 2 is called even number.

An integer that is not an even number is an odd number.

Generally, the last digit of even number is 0, 2, 4, 6 or 8.

### Program to find even numbers

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#include<stdio.h> int main() { int i=0; int num=0; printf("Enter the number\n"); scanf("%d\n", &num); printf("List of even numbers upto %d is\n", num); for(i=0; i<=num; i++) { if(i%2 == 0) { printf("%d \t", i); } } } |

**Output**

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Enter the number 20 List of even numbers up to 20 is 0 2 4 6 8 10 12 14 16 18 20 |

Explanation:

In above program, first of all, we take a number i.e. 20 as an input from the user.

We are going to print all *even* numbers from 0 to input number i.e. 20.

Here for looping, we use for loop.

The **for** loop will give us one by one number like 1,2,3… up to limit i.e.20.

So we are going to check each number one by one by using control statement **if**.

**if** is used to check given number is *even* or not.

If a number is even it get print otherwise next number will check.

In this way, we will get a list of all *even* numbers up to 20.

### Program to find odd numbers

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#include<stdio.h> int main() { int i=0; int num=0; printf("Enter the number\n"); scanf("%d\n", &num); printf("List of odd numbers upto %d is\n", num); for(i=0; i<=num; i++) { if(i%2 != 0) { printf("%d \t", i); } } } |

**Output**

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Enter the number 44 List of odd numbers upto 44 is 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 |

### Ankit Wasankar

Senior Java Developer

Java 11 | Microservices | Reactjs | SQL