C-Language-Programs Archives - WebEncyclop Tutorials

Write a C program to find LCM of numbers

September 13, 2018 by Ankit Wasankar

Problem statement:

What is LCM of numbers
LCM is a least common factor of given two numbers

Given: input1 = 4 and input2 = 5
then answer is LCM = 20

Write a C program to find LCM of numbers

#include<stdio.h>
int main()
{
  int n1, n2, t1, t2;
  printf("Enter n1 and n2 : ");
  scanf("%d %d", &n1, &n2);
  t1 = n1;
  t2 = n2;
  if(n1 > n2)
  {
    for(; n1%n2!=0; n1=n1+t1){}
    printf("LCM is %d",n1);
  }

  if(n2 > n1)
  {
    for(; n2%n1!=0; n2=n2+t2){}
    printf("LCM is %d",n2);
  }
  getch();
}

#include<stdio.h>

int main()

{

int n1, n2, t1, t2;

printf("Enter n1 and n2 : ");

scanf("%d %d", &n1, &n2);

t1 = n1;

t2 = n2;

if(n1 > n2)

{

for(; n1%n2!=0; n1=n1+t1){}

printf("LCM is %d",n1);

}

if(n2 > n1)

{

for(; n2%n1!=0; n2=n2+t2){}

printf("LCM is %d",n2);

}

getch();

}

Output

Enter n1 and n2 : 2 3
LCM is 6

1 2	Enter n1 and n2 : 2 3 LCM is 6

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program to perform arithmetic operations using switch case statement

September 13, 2018 by Ankit Wasankar

Problem statement:

Write a C program to take two numbers and operator as input then perform arithmatic operation depending on input operator.

Write a C program to perform arithmetic operations on two numbers using switch case

#include<stdio.h>
int main()
{
  int n,m,t; 
  char c;
  printf("Enter two numbers and operator :\n");
  scanf("%d %d %c", &n, &m, &c);

  switch(c)
  {
     case '+' : printf("Addition is : %d", n+m);
                break;
     case '-' : printf("Substraction is %d", n-m);
                break;
     case '*' : printf("Multiplication is %d", n*m);
                break;
     case '/' : printf("Division is %f", (float)n/m);
                break;
     default  : printf("Not valid");
  }

  getch();
  return 0;
}

#include<stdio.h>

int main()

{

int n,m,t;

char c;

printf("Enter two numbers and operator :\n");

scanf("%d %d %c", &n, &m, &c);

switch(c)

{

case '+' : printf("Addition is : %d", n+m);

break;

case '-' : printf("Substraction is %d", n-m);

break;

case '*' : printf("Multiplication is %d", n*m);

break;

case '/' : printf("Division is %f", (float)n/m);

break;

default : printf("Not valid");

}

getch();

return 0;

}

Output

Enter two numbers and operator :
2 8 /
Division is 0.250000

Enter two numbers and operator :

2 8 /

Division is 0.250000

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C program to reverse a number

September 13, 2018September 13, 2018 by Ankit Wasankar

Problem statement

Write a program to reverse a number using loop.
input1 = 1234

Then answer: output1 = 4321

Write a C program to reverse a number.

#include<stdio.h>
int main()
{
  int p, n=0;
  printf("Enter 4 digit number:\n");
  scanf("%d", &p);
  printf("Reverse of a given number is:\n");

  while(p >= 1)
  {
    n = p%10;
    p = p/10;
    printf("%d", n);
  }

  getch();
  return 0;
}

#include<stdio.h>

int main()

{

int p, n=0;

printf("Enter 4 digit number:\n");

scanf("%d", &p);

printf("Reverse of a given number is:\n");

while(p >= 1)

{

n = p%10;

p = p/10;

printf("%d", n);

}

getch();

return 0;

}

Output

Enter 4 digit number :
123456789
Reverse of a given number is:
987654321

Enter 4 digit number :

123456789

Reverse of a given number is:

987654321

Problem statement

Write a program to take 4 digit any number as input from the user and reverse that number but only using operators(or without using any function)

Write a C program to reverse 4 digit number only with help of operators or without using function/loop

#include<stdio.h>
int main()
{
  int p, n1, n2, n3, n4, num;
  printf("Enter 4 digit number:\n");
  scanf("%d",&p);

  n1 = p%10;
  p  = p/10;
  n2 = p%10;
  p  = p/10;
  n3 = p%10;
  p  = p/10;
  n4 = p%10;

  num = 1000*n1 + 100*n2 + 10*n3 + n4;

  printf("Reverse of given number is %d", num);
  getch();
  return 0;
}

#include<stdio.h>

int main()

{

int p, n1, n2, n3, n4, num;

printf("Enter 4 digit number:\n");

scanf("%d",&p);

n1 = p%10;

p = p/10;

n2 = p%10;

p = p/10;

n3 = p%10;

p = p/10;

n4 = p%10;

num = 1000*n1 + 100*n2 + 10*n3 + n4;

printf("Reverse of given number is %d", num);

getch();

return 0;

}

Output

 
Enter 4 digit number:
1234
Reverse of given number is 4321

Enter 4 digit number:

1234

Reverse of given number is 4321

Explanation

Enter 4 digit number:  1234
so P = 1234

n1= p%10;       n1 = 1234 % 10 
                   = 4
p = p/10;       p  = 1234 / 10
                   = 123
n2 = p%10;      n2 = 123 % 10
                   = 3
p = p/10;       p  = 123 / 10
                   = 12
n3 = p%10;      n3 = 12 % 10
                   = 2
p = p/10;       p  = 12 / 10
                   = 1
n4 = p%10;      n4 = 1 % 10
                   = 1

NOW, num = 1000*n1 + 100*n2 + 10*n3 + n4;
         = 1000*4  + 100*3  + 10*2  + 1
         = 4000 + 300 + 20 + 1
         = 4321

Enter 4 digit number: 1234

so P = 1234

n1= p%10; n1 = 1234 % 10

= 4

p = p/10; p = 1234 / 10

= 123

n2 = p%10; n2 = 123 % 10

= 3

p = p/10; p = 123 / 10

= 12

n3 = p%10; n3 = 12 % 10

= 2

p = p/10; p = 12 / 10

= 1

n4 = p%10; n4 = 1 % 10

= 1

NOW, num = 1000*n1 + 100*n2 + 10*n3 + n4;

= 1000*4 + 100*3 + 10*2 + 1

= 4000 + 300 + 20 + 1

= 4321

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C Program to Sort Words in Lexicographical Order (Dictionary Order)

August 19, 2018 by Ankit Wasankar

Problem statement

Write a program to take words or elements as input from user and sort it as Lexicographical/Dictionary order.

What is meant by Lexicographical Order:

Lexicographical Order is also known as lexical order, dictionary order, alphabetical order, lexicographic order.
Lexicographic order is the way of ordering of words based on the alphabetical order of their component letters.
It is similar to the way in we search any word in the dictionary.

Example:
Suppose following numbers: Ram, Rita, Abhinav, Abhish, Rina, Josh.
Now Lexicographical Order is- Abhinav, Abhish, Josh, Ram, Rina, Rita.

Program to Sort Strings in Lexicographical/Dictionary Order

#include<stdio.h>
#include<string.h>
int main()
{
  int i,j;   
  char str[10][50]={"ram narayan","sita vishnupanth","rita","raj kumar","lakshman sheth","rina rao"};
  char temp[50];
  //sorting elements in order
  for(i=0;i<9;i++)
    {
    for(j=i+1;j<10;j++)
      {
        if(strcmp(str[i],str[j])>0)
          {
            strcpy(temp,str[i]);
            strcpy(str[i],str[j]);
            strcpy(str[j],temp);
          }
      }
    }
  //printing sorted elements 
  printf("In lexicographical order: \n");
  for(i=0;i<10;++i)
    {
      printf(str[i]);
      printf("\n");
    }
}

#include<stdio.h>

#include<string.h>

int main()

{

int i,j;

char str[10][50]={"ram narayan","sita vishnupanth","rita","raj kumar","lakshman sheth","rina rao"};

char temp[50];

//sorting elements in order

for(i=0;i<9;i++)

{

for(j=i+1;j<10;j++)

{

if(strcmp(str[i],str[j])>0)

{

strcpy(temp,str[i]);

strcpy(str[i],str[j]);

strcpy(str[j],temp);

}

//printing sorted elements

printf("In lexicographical order: \n");

for(i=0;i<10;++i)

{

printf(str[i]);

printf("\n");

}

Output:

In lexicographical order: 

lakshman sheth
raj kumar
ram narayan
rina rao
rita
sita vishnupanth

In lexicographical order:

lakshman sheth

raj kumar

ram narayan

rina rao

rita

sita vishnupanth

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Program to find maximum difference between two elements such that larger element appears after the smaller number

March 23, 2018March 23, 2018 by Ankit Wasankar

Problem statement
Maximum difference between two elements such that larger element appears after the smaller number

Explanation:
Given an array arr[] of integers, find out the difference between any two elements such that larger element appears after the smaller number in arr[].

Examples:

If array is [2, 3, 10, 6, 4, 8, 1] then returned value should be 8 (Diff between 10 and 2).
If array is [ 7, 9, 5, 6, 3, 2 ] then returned value should be 2 (Diff between 7 and 9)

Conclusion:
You have to take first number of array and check it with remaining array elements.
Then find the largest number in remaining array (excluding number at array index 0).
Then find the difference between largest number from remaining array and first number from array.
This will be the largest difference between two elements.

C program to find maximum difference between two elements such that larger element appears after the smaller number

#include<stdio.h>
int main()
{
    int arr[100],i=0,j=0,diff=0,n=0;
    printf("Enter array size\n");
    scanf("%d",&n);
    printf("Enter elements of array\n");
  
    for(i=0;i<n;i++)
    {
      scanf("%d",&arr[i]);
    }

    i=0;
    diff= arr[i+1]-arr[i];

    for(i=0;i<n;i++)
    {
      for(j=i+1;j<n;j++)
      {
         if(diff<(arr[j]-arr[i]))
          {
              diff=arr[j]-arr[i];
          }
       }
    }
    printf("The maximum difference is %d",diff);
}

#include<stdio.h>

int main()

{

int arr[100],i=0,j=0,diff=0,n=0;

printf("Enter array size\n");

scanf("%d",&n);

printf("Enter elements of array\n");

for(i=0;i<n;i++)

{

scanf("%d",&arr[i]);

}

i=0;

diff= arr[i+1]-arr[i];

for(i=0;i<n;i++)

{

for(j=i+1;j<n;j++)

{

if(diff<(arr[j]-arr[i]))

{

diff=arr[j]-arr[i];

}

printf("The maximum difference is %d",diff);

}

Output:

Enter array size
6
Enter elements of array
7 9  5 6 3 2
The maximum difference is 2

Enter array size

Enter elements of array

7 9 5 6 3 2

The maximum difference is 2

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C program to print a pattern

March 3, 2018 by Ankit Wasankar

Pattern Problem – 5

You need to take an integer input and then draw the pattern according to it. Say for example if you enter 5 then, the pattern should be like this-

5 5 5 5 5

4 4 4 4 4

3 3 3 3 3

2 2 2 2 2

1 1 1 1 1

Input Format
You will take an integer input n from stdin.

Constraints
1 <= n <= 1000 Output Format
Your output should be the pattern according to the input which you had entered.

Sample TestCase 1
Input
5
Output:

5 5 5 5 5

4 4 4 4 4

3 3 3 3 3

2 2 2 2 2

1 1 1 1 1

Write a C program to print the following pattern

5 5 5 5 5 4 4 4 4 4 3 3 3 3 3 2 2 2 2 2 1 1 1 1 1

1
2
3
4
5

5 5 5 5 5
4 4 4 4 4
3 3 3 3 3
2 2 2 2 2
1 1 1 1 1

#include<stdio.h>
int main()
{
	int n=0,i=1;
	scanf("%d",&n);
	int num=n;
	while(n>0)
	{
	    for(i=1;i<=num;i++)
	    {
	        printf("%d ",n);
	    }
	    printf("\n");
	    n--;
	}
}

#include<stdio.h>

int main()

{

int n=0,i=1;

scanf("%d",&n);

int num=n;

while(n>0)

{

for(i=1;i<=num;i++)

{

printf("%d ",n);

}

printf("\n");

n--;

}

Output:

5 5 5 5 5

4 4 4 4 4

3 3 3 3 3

2 2 2 2 2

1 1 1 1 1

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C program to print below program – Pattern problem 4

March 3, 2018 by Ankit Wasankar

You need to take an integer input and then draw the pattern according to it.
Say for example if you enter 6 then, the pattern should be like this-

A B C D E 
A B C D E 
A B C D E 
A B C D E 
A B C D E

A B C D E

Input Format
You will take an integer input n from stdin.

Constraints
1 <= n <= 1000

Output Format
Your output should be the pattern according to the input which you had entered.

Sample TestCase 1
Input
5
Output:

A B C D E
A B C D E
A B C D E
A B C D E
A B C D E

A B C D E

Write a C program to print following pattern

A B C D E A B C D E A B C D E A B C D E A B C D E

1
2
3
4
5

A B C D E
A B C D E
A B C D E
A B C D E
A B C D E

#include<stdio.h>
int main()
{
	
	int n=0;
	int i=1,j=0;
	scanf("%d",&n);
	int num=n;
	while(n>0)
	{
	    for(i=1,j=65;i<=num;i++)
	    {
	    printf("%c ",j);
	    j++;
	    }
	    printf("\n");
	    n--;
	}

}

#include<stdio.h>

int main()

{

int n=0;

int i=1,j=0;

scanf("%d",&n);

int num=n;

while(n>0)

{

for(i=1,j=65;i<=num;i++)

{

printf("%c ",j);

j++;

}

printf("\n");

n--;

}

Output

A B C D E
A B C D E
A B C D E
A B C D E
A B C D E

A B C D E

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C program to draw a pattern

March 3, 2018 by Ankit Wasankar

You need to take an integer input and then draw the pattern according to it.
Say for example if you enter 5 then, the pattern should be like this-
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5

Input Format
You will take an integer input n from stdin.

Constraints
1 < = n < = 1000 Output Format
Your output should be the pattern according to the input which you had entered.

Sample TestCase 1
Input
5
Output

1 2 3 4 5

Write a C program to print following pattern

1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5

1
2
3
4
5

1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5

Program:

#include<stdio.h>
int main()
{
	int n;
	int i=1;
	scanf("%d",&n);
	int num=n;
	while(n>0)
	{
	    for(i=1;i<=num;i++)
	    {
	    printf("%d ",i);
	    }
	    printf("\n");
	    n--;
	}
}

#include<stdio.h>

int main()

{

int n;

int i=1;

scanf("%d",&n);

int num=n;

while(n>0)

{

for(i=1;i<=num;i++)

{

printf("%d ",i);

}

printf("\n");

n--;

}

Output:

1 2 3 4 5

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C program to print below program – Pattern problem 2

March 3, 2018 by Ankit Wasankar

You need to take an integer input and then draw the pattern according to it.
Say for example if you enter 6 then, the pattern should be like this-

* * * * * 
* * * * * 
* * * * * 
* * * * * 
* * * * * 
* * * * *

* * * * *

Input Format
You will take an integer input n from stdin.

Constraints
1 <= n <= 1000

Output Format
Your output should be the pattern according to the input which you had entered.

Sample TestCase 1
Input
6
Output:

* * * * *
* * * * *
* * * * *
* * * * *
* * * * *
* * * * *

* * * * *

Program to print

* * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

1
2
3
4
5
6

* * * * *
* * * * *
* * * * *
* * * * *
* * * * *
* * * * *

#include<stdio.h>
int main()
{
	int n;
	
	scanf("%d",&n);
	while(n>0)
	{
	    printf("* * * * *\n");
	    n--;
	}
}

#include<stdio.h>

int main()

{

int n;

scanf("%d",&n);

while(n>0)

{

printf("* * * * *\n");

n--;

}

Output

* * * * *
* * * * *
* * * * *
* * * * *
* * * * *
* * * * *

* * * * *

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C program to find simple and compound interest

February 1, 2018 by Ankit Wasankar

Problem statement

Write a program to calculate simple interest and compound interest.
Here we will take principle, time and rate of as input from user.

What is compound interest

The concept of compound interest is that interest is added back to the principal sum so that interest is earned on that added interest during the next compounding period.

The formula for calculating compound interest is:

= [P (1 + i)n] – P
= P [(1 + i)n – 1]

Where
P = Principal,
i = annual interest rate in percentage terms,
n = number of compounding periods.

What is simple interest

Simple interest is a quick method of calculating the interest charge on a loan. Simple interest is determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.

The formula for calculating compound interest is:

Simple Interest = Interest Rate x Principal Balance

What is Principle

Principal is the money used to pay down the balance of the loan.
The principal is the amount you are borrowing, and the interest is the charge for the time you have the loan.

What is Interest

Interest is the charge paid to the lender for the privilege of borrowing the money.
Interest is calculated on the principal.

Program to calculate the interest

#include<stdio.h>
#include<math.h>
int main()
{
        int p,t;
        float r,si,amount,ci;
        printf("Enter principal,time and rate of interest\n");
        scanf("%d%d%f",&p,&t,&r);

       //calculating simple interest
        si=p*t*r/100;
        printf("Simple interest is = %f\n",si);
        
        //calculating compound interest
        amount=p*pow((1 +r/100),t);
        ci=amount-p;
        printf("Compound interest = %f",ci);
}

#include<stdio.h>

#include<math.h>

int main()

{

int p,t;

float r,si,amount,ci;

printf("Enter principal,time and rate of interest\n");

scanf("%d%d%f",&p,&t,&r);

//calculating simple interest

si=p*t*r/100;

printf("Simple interest is = %f\n",si);

//calculating compound interest

amount=p*pow((1 +r/100),t);

ci=amount-p;

printf("Compound interest = %f",ci);

}

Output:

Enter principal,time and rate of interest
2154  2   4
Simple interest is = 172.320007
Compound interest = 175.766113

Enter principal,time and rate of interest

2154 2 4

Simple interest is = 172.320007

Compound interest = 175.766113

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Problem statement:

Write a C program to find LCM of numbers

Write a C program to perform arithmetic operations on two numbers using switch case

Problem statement

Write a C program to reverse a number.

Problem statement

Write a C program to reverse 4 digit number only with help of operators or without using function/loop

Problem statement

What is meant by Lexicographical Order:

Program to Sort Strings in Lexicographical/Dictionary Order

C program to find maximum difference between two elements such that larger element appears after the smaller number

Write a C program to print the following pattern 5 5 5 5 5 4 4 4 4 4 3 3 3 3 3 2 2 2 2 2 1 1 1 1 1 12345 5 5 5 5 54 4 4 4 43 3 3 3 32 2 2 2 21 1 1 1 1

Write a C program to print following pattern A B C D E A B C D E A B C D E A B C D E A B C D E 12345 A B C D EA B C D EA B C D EA B C D EA B C D E

Write a C program to print following pattern 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 12345 1 2 3 4 51 2 3 4 51 2 3 4 51 2 3 4 51 2 3 4 5

Program to print * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * 123456 * * * * ** * * * ** * * * ** * * * ** * * * ** * * * *

Problem statement

What is compound interest

The formula for calculating compound interest is:

What is simple interest

The formula for calculating compound interest is:

What is Principle

What is Interest

Program to calculate the interest

Write a C program to print the following pattern

5 5 5 5 5 4 4 4 4 4 3 3 3 3 3 2 2 2 2 2 1 1 1 1 1

1
2
3
4
5

5 5 5 5 5
4 4 4 4 4
3 3 3 3 3
2 2 2 2 2
1 1 1 1 1

Write a C program to print following pattern

A B C D E A B C D E A B C D E A B C D E A B C D E

1
2
3
4
5

A B C D E
A B C D E
A B C D E
A B C D E
A B C D E

Write a C program to print following pattern

1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5

1
2
3
4
5

1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5

Program to print

* * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

1
2
3
4
5
6

* * * * *
* * * * *
* * * * *
* * * * *
* * * * *
* * * * *